in garden peas, smooth seed coat is dominant over rinkled seed coat. these trait

Question

in garden peas, smooth seed coat is dominant over rinkled seed coat. these traits are alleles. A homozygous smooth seeded plant is crossed with a homozygous wrinkled seeded plant. Calculate the F1 and F2 generations.

Explanation / Answer

Let the S allele = smooth seed coat (dominant) Let the s allele = wrinkled seed coat (recessive) Homozygous smooth seeded plant = SS genotype Homozygous wrinkled seeded plant = ss genotype Parental (P) cross: SS x ss --> Mendel's law of segregation says allele pairs segregate during gamete formation SS genotype will produce gamete containg the S allele ss genotype will produce gamete containing the s allele Fusion of gametes gives F1 Generation: Ss (smooth seeded plant) F1 x F1 --> F2 Generation Ss x Ss Both Ss gentoypes in the cross above will produce gametes containing both the S and s alleles. We must draw a punnett square to solve for the genotypic and phenotypic ratios in the F2 generation. Draw a square with four boxes. On the side, you'l haev the gametes S and s. Do the same thing for the top. You should end up with the following genotypes: 1/4SS, 2/4/Ss = 1/2Ss, 1/4ss --> gentotypic ratio is 1:2:1 and phenotypic ratio is 3:1 (3 smooth seeded and 1 wrinkled seeded) Hope this helps! :-)

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