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Question

%3Cp%3EAn%20engine%26nbsp%3Btakes%26nbsp%3Bin%26nbsp%3B10%5E8%26nbsp%3BJ%26nbsp%3Bat%26nbsp%3Ba%26nbsp%3Btemperature%26nbsp%3Bof%26nbsp%3B500%26nbsp%3BK%2C%26nbsp%3Brejects%26nbsp%3B5x10%5E7%26nbsp%3BJ%26nbsp%3Bat%26nbsp%3Ba%26nbsp%3Btemperature%26nbsp%3Bof%26nbsp%3B250%26nbsp%3BK%26nbsp%3Band%26nbsp%3Bdelivers%26nbsp%3B10%26nbsp%3Bkilo-watt%26nbsp%3Bhrs%26nbsp%3Bof%26nbsp%3Bmechanical%26nbsp%3Bwork.%26nbsp%3BWhat%26nbsp%3Bare%26nbsp%3Ba).%26nbsp%3Bthe%26nbsp%3Bexpected%26nbsp%3Bmaximum%26nbsp%3Befficiency%26nbsp%3Band%26nbsp%3Bb).%26nbsp%3Bthe%26nbsp%3Breal%26nbsp%3Befficiency%26nbsp%3Bof%26nbsp%3Bthe%26nbsp%3Bengine%3C%2Fp%3E

Explanation / Answer

specific heat of water is 4.186 kJ/kgC

heat of fusion of ice is 334 kJ/kg

E = [334 kJ/kg x 0.2 kg] + [ 4.186 kJ/kgC x 0.2 kg x 60C ]

E = 66.8 + 50.23 kJ = 117.03 kJ

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