A. Determine the magnitude and direction of the current induced in the circuit a

Question

A. Determine the magnitude and direction of the current induced in the circuit as it is moving into the magnetic field.

B.Determine the magnitude and direction of the current induced in the cicuit as it is totally within the magnetic field, but still moving.

C. Determine the magnitude and direction of the current induced in the circuit as it is moving out of the field.

A rectangular circuit is moved at a constant velocity of 3.0 m/s into, through, and then out of a uniform 1.25 T magnetic field. The magnetic field region is considerably wider than 50.0 cm.

Explanation / Answer

a)
FIRST CASE:
As the circuit is moving into the magnetic field, the magnetic fluxincreases. The induced current in the loop tries to reducethat magnetic flux by setting a magnetic field into the page. Thus, the induced current for the first case would be clockwise.
induced emf e=B*L*V=1.25*.75*3=2.1825 V..

current i=e/R=2.1825/12.5=0.225 A

SECOND CASE:
Once the circuit is completely inside the magnetic field, magneticflux is no longer changing. Thus, there is no induced current.

THIRD CASE:
As the circuit is moving out of the magnetic field, the magneticflux decreases. The induced current in the loop tries toincrease the magnetic flux by settinga magnetic field out ofthe page. Thus, the induced current for the third case wouldbe counterclockwise.

induced emf e=B*L*V=1.25*.75*3=2.1825 V..

current i=e/R=2.1825/12.5=0.225 A

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