Water flows steadily from an open tank as shown in the figure. ( Figure 1 ) The

Question

Water flows steadily from an open tank as shown in the figure. (Figure 1) The elevation of point 1 is 10.0m , and the elevation of points 2 and 3 is 2.00m . The cross-sectional area at point 2 is 4.80

Water flows steadily from an open tank as shown in the figure. (Figure 1) The elevation of point 1 is 10.0m , and the elevation of points 2 and 3 is 2.00m . The cross-sectional area at point 2 is 4.80 times 10?2m2 ; at point 3, where the water is discharged, it is 1.60 times 10?2m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe Assuming that Bernoulli's equation applies, compute the volume of water ?V that flows across the exit of the pipe in 1.00s . In other words, find the discharge rate ?V/?t.

Explanation / Answer

volume of liquid coming out per 1 sec is.

V=A*sqrt(2gh)

where,

h is depth of orifice from the top surface of the fluid

h=10-2=8 m

so,

V=1.6*10^-2*sqrt(2*9.8*8)

V=0.20035 m^3 .............is answer

or

V=0.20035*10^3 L

V=200.3516 L ......is answer

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