Its number 4, I need help determining part c and d. whose normal to the area is
ID: 2254791 • Letter: I
Question
Its number 4, I need help determining part c and d.
Explanation / Answer
At q3 equate the vertical components of forces F1 and F2
i.e, F1 sin (53) = F2 sin(37)
1/4pie q2q3 sin(53)/3^2 = 1/4pie q1q3 sin(37)/4^2
16q2 sin(53) = 9q1 sin(37)
q2 = 9/16 q1 sin(37)/sin(53)
= 9/16*(-4)*3/5*5/4
= -27/16
= -1.6875
F= F1 cos(53)+F2cos(37)
= 1/4pie [(q2q3)/9 cos53 + (q1q3)/16 cos(37)]
= 9x10^9 * [(-27/16)/9*3/5 - 4/16 * 4/5 ]
= 9x10^9x[-9/80 - 1/5]
= -25/80x9x10^9
= - 2.8125x10^9 N
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