1)How much energy in J has been dissipated by the time the mass comes to a rest?
ID: 2254764 • Letter: 1
Question
1)How much energy in J has been dissipated by the time the mass comes to a rest?
E = .65 J
2)What is the mass of water in the container in kg ?
m(water) =10 kg
3)Assuming that the water with the block are thermally isolated from their surroundings, by how much will their temperature increase? Express your answer in C . You will need the values of the heat capacity: c(water)=4186 J/kg*C , c(iron)=448 J/kg*C .
Delta T = ___________________ c
Explanation / Answer
1.)Energy dissipiated=1/2*K*x^2
=1/2*130*0.1^2
=0.65 J ans
2.)mass=density*volume
=1000*10*10^-3
=10 Kg
3.)10*4186*detaT=0.65
deltaT=1.55*10^-5 K ans
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