1- A hydraulic jack for changing car tires is designed with a primary cylinder (
ID: 2254626 • Letter: 1
Question
1- A hydraulic jack for changing car tires is designed with a primary cylinder (the one you push down on) 1 cm in diameter and a secondary cylinder (the one that pushes up on the car) 5cm in diameter. You get a mechanical advantage of five -to-one from the level on the device as well (that is, the force on the cylinder is five times the force you apply to the lever). If you push down on the lever with 250 N, how much force acts to lift the car? Ignore any difference in height.
2- A steel meter stick is correctly calibrated at 20 degrees Celsius. How long would it be in a commercial freezer which is maintained at -5 degrees Celsius?
Explanation / Answer
1)
Force on primary cylinder = 5*250 = 1250N
for hydraulic jack F(primary)/A(primary) = F(secondary)/A(secondary)
F(secondary) = 1250*(5/1)^2 = 31250N
2) Thermal expansion at 20deg centigrade =13*10^-6
Length would be = 1(1-13*10^-6 * 25) = 0.9997m
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