A pendulum consisting of a ball of mass m hanging from a massless rope is droppe

Question

A pendulum consisting of a ball of mass m hanging from a massless rope is dropped from a height h. It collides with a block of mass 2m at the bottom of its swing. How high does the ball on the pendulum rebound from its collision with the block? Assume the collision is perfectly elastic. A pendulum consisting of a ball of mass m hanging from a massless rope is dropped from a height h. It collides with a block of mass 2m at the bottom of its swing. How high does the ball on the pendulum rebound from its collision with the block? Assume the collision is perfectly elastic.

Explanation / Answer

1/2m*v^2=mgh
v=?2gh=?19.6h

momentum conservation

m119.6h=m1V2+m2u2

elastic collision

co eff of resitution is 1 for elastic collision

1=V2-u2/V1=

V2-u2=V1==>u2=V2-V1

now put u2 in momentum equation we will find V2

and after V21=?2*gH

where H is the height of rebound

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.