A solid metal sphere of radius R has charge +2Q. A hollow spherical shell of rad

Question

A solid metal sphere of radius R has charge +2Q. A hollow spherical shell of radius 3R placed concentric with the first sphere has net charge -Q.

If the spheres were joined by a conducting wire, what would the electric field and the potential be at a distance r from the center of the inner sphere (R<r<3R)

A solid metal sphere of radius R has charge +2Q. A hollow spherical shell of radius 3R placed concentric with the first sphere has net charge -Q. If the spheres were joined by a conducting wire, what would the electric field and the potential be at a distance r from the center of the inner sphere (R

Explanation / Answer

inside the inner sphere, a closed spherical surface encloses no charge, so E is 0 between spheres, the outer sphere is irrelevant, only the 2 Q matters E drops off with 1/r^2, the surface area of spherical surface.

outside sphere 2

we surround a total of 2Q-Q = 1 Q

field again drops off as 1/r^2

for R<r<3R

E = 2 Q/(4 *pi *r^2 *eo)

and we know E=-(dV/dr)

therefor V=Er= 2 Q/(4 *pi* r* eo)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.