PLEASE DONT WASTE MY TIME Maddy r YouTube × * Lecture Notes: MAS3 \\ Uni 1 Notes

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PLEASE DONT WASTE MY TIME

Maddy r YouTube × * Lecture Notes: MAS3 Uni 1 Notes pdf X @ Do Homework Nad x G Chegg Study Guidec × coisecure https://www.mathul ::: Apps eSantaFr Sant Fr Q, Mail Flamin,Nadir1serDashbard N Kindle Cloud Reader 9 Sling TVis Ala Cart D Physics for Snentists Matrix Reduced ow E × Lil Wayne Radio 1.4 x G ' MAS 3114, Computational Liner Algebra, Spring 2018 Nadir Eamin | 1/18/18 5:32 PM Homework: MO2(HW) Row Reduction & Echelon Forms (1.2) Save Score: 0 of 1 pt X 1.2.14 nd th general solution of the system whose augmented metrix 5 ot 12 (5 complete) HW Score: 33.33%, 4 of 12 pts Question Help * given below 10-3 0-5 6 01 7-1 0 B 00 0 0 1 0 Select the correct choice below and, if necessary, fil in any answer boxes to complete your answer. OB. O C. D. The system is inconsistent. = 14Kg x is free xy is free X4 Ks s tree .. 1· ./i :/il .. !! (La) More Click to select and enter your answer's) and then click Check Answer All parts showing Clear AI Check Answer --og1/1322018 Type here to search 1182018 3

Explanation / Answer

Convert the given matrix to Row Echelon form

Make zeros in column 1 except entry at row 1, column 1 (pivot entry).

As can be seen all elements in column (except pivot) are already zero.

Make zeros in column 2 except entry at row 2, column 2 (pivot entry).

As can be seen all elements in column (except pivot) are already zero.

Since element at row 3 and column 3 (pivot element) equals 0, we need to swap rows.

Find the first non-zero element in the column 3 under the pivot entry.

As can be seen, there are no such entries. So, move to the next column.

Since element at row 3 and column 4 (pivot element) equals 0, we need to swap rows.

Find the first non-zero element in the column 4 under the pivot entry.

As can be seen, there are no such entries. So, move to the next column.

Make zeros in column 5 except entry at row 3, column 5 (pivot entry).

Add row 3 multiplied by 55 to row 1 (R1=R1+(5)R3)

Therefore the matrix is

[1 0 -3 0 0 6

0 1 7 -1 0 8

0 0 0 0 1 0

0 0 0 0 0 0]

(Since all rows below are zero, then we are done.

since the last row are all zeros we have no solution for this system

Therefore the system is Inconsistent

Option D

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