If you have an L-point running average filter and you are applying this filter o

Question

If you have an L-point running average filter and you are applying this filter on a given signal xx, doubling the length of the averager to be 2L will produce a smoother output without any extra computation cost. produce the same output as the one produced by the L-point averager. produce a smoother output with extra computation cost but the length of the increase the computational cost without affecting the output. output signal is the same as the one produced with the L-point averager produce a smoother output with extra computation cost and the output signal is longer than the one produced by the L-point averager, Submit

Explanation / Answer

Produce smoother output with extra computation cost but the length of the output signal is same as one produced with L point averager because if you increase the length of filter it attenuates pass band ripples and get smoother output.but the output signal will not vary. But efficiently signal can be passed because you are taking more averages so the precise value of error u will get which is small

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