replay the game does not work.It can not recognize “n” when you want to quit. in

Question

replay the game does not work.It can not recognize “n” when you want to quit. include int main (int argc, char **argv) t int a 1; number between 1 and 100 and press "); while (a){ printf("Thinkf int high=100; int low=1; a char str; while (high >= low) { getchar) int mid= (high + low) / 2; printf ("Is it higher than d? y/n)n",mid) scanf (&str;) if ( str=-'y ') { low= (mid+1 ) ; } else if ( str== 1 n' ) { high= (mid-1); }else {printf ("Type yar n"); printf(" >>>>>> The number is %d ",high+1); to continue playing (y/n) ?1n) printf ("Do you want scanf ( "%c", &str;) ; getchar ) if ( str== n' ) { a=0; } ("Thanks for playing!!!")

Explanation / Answer

just put a space before %c in scanf statements as it takes as the character input by using return statement. Space will consume that newline character.

#include <stdio.h>

int main(void)

{

int a = 1;

while(a)

{

printf(" Think of a number between 1 and 100 and press <enter> ");

int high = 100;

int low = 1;

char str;

while(high >= low)

{

getchar();

int mid = (high + low)/2;

printf("Is it higher than %d? (y/n) ",mid);

scanf(" %c",&str);

if(str == 'y')

low = mid+1;

else if(str == 'n')

high = mid - 1;

else

printf("Type y or n");

}

printf(" >>>>>>>The number is %d ",high+1);

printf(" Do you want to continue playing(y/n) ");

scanf(" %c",&str);

getchar();

if(str == 'n')

a = 0;

}

printf(" Thanks for playing");

return 0;

}

Output:

Think of a number between 1 and 100 and press <enter> 45
Is it higher than 50? (y/n)
Type y or n n

Is it higher than 50? (y/n) n
Is it higher than 25? (y/n)y
Type y or n y

Is it higher than 25? (y/n)
Is it higher than 37? (y/n)
Type y or n y

Is it higher than 37? (y/n)
Is it higher than 43? (y/n)
Type y or n Is it higher than 43? (y/n)
Is it higher than 40? (y/n)
Is it higher than 38? (y/n)

>>>>>>>The number is 38

Do you want to continue playing(y/n)

Thanks for playing

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