(4 points) The corporate IT group has assigned your company the Class C network

Question

(4 points) The corporate IT group has assigned your company the Class C network address of 192.168.54.0 / 24. You must subnet this network in order to have as many subnets as possible containing at least 5 hosts per subnet.  

How many subnets would be created?

What is the mask that would be used? (give both dotted decimal and CIDR notation)

What are the possible subnet addresses? (don’t need to list every one, just enough to give the idea)

5. (3 points) Your university has assigned you the Class C network of 192.168.203.0 for distribution among eight floors of the library for public internet terminal access. Each floor will have 10 public internet terminals (these are the only hosts that will be on this subnet).    What subnet mask would be used for this scenario?   What would be the subnet addresses for the created subnets?   How many subnets are still available for use after you have assigned the networks?

6. (1 point) What is the broadcast address for the network 192.168.47.0/24?

7. (1 point) What is the broadcast address for the network 192.168.47.204/30?

8. (1 point) Given the subnet mask /26 are the following two hosts on the same subnet?

Host A:   129.50.72.100

Host B: 129.50.72.95

Why or why not?

Explanation / Answer

4. in the Address 192.168.54.0 / 24 we have total of 256 addresses including 1 broadcast and 1 network address. Now our requirement is that we must have atleast 5 hosts per subnet. 1 address should be there as broadcast address and 1 as network address. So each subnet will have 5+1+1 = 7 addresses. But a subnet can have addresses only in exponents of 2. So each will have 8 addresses.

So leaving broadcast and network address of the main network, we have 254 hosts which we need to divide into subnets. So maximum number of subnets are ceil( 254/8 ) = 32. So max number of subnets are 32. Each will have 6 hosts and 2 IPs for subnet address and broadcast address.

Masks for each subnet will be 255.255.255.248 or /29

Subnet addresses will be like First subnet will have subnet address : - 192.168.54.0/29

Now next will have subnet address which will be 8th after this address i.e. 192.168.54.8 / 29, Next will be next 8th i.e. 192.168.54.16/29

So we'll keep on adding 8 to previous subnet address to get the next subnet address.

In this way last address will be 192.168.54.248/29 which will be of 32th subnet address.

5. 192.168.203.0  - This is a Class C address so, the subnet mask of this address is /24 So it will have 256 addresses . We need 8 subnets with atleast 10 hosts per subnet.. So we need a subnet will 16 IPs each.

So the mask used for subnets is 255.255.255.240 / 28 with each subnet containing 14 hosts , 1 subnet address and 1 broadcast address.

So subnet addresses of 8 subnets are : -

192.168.203.0 /28

Apart from these 8 more subnets can be created.

6. Broad cast address is the last address of the address range. Here last address is 192.168.47.255, which is broadcast address.

7. 192.168.47.207 is the broadcast address.

8. Yes they are of same subnet. The address range of this subnet is : - 129.50.72.65 to 129.50.72.126

Both lies in this address range, So both belongs to same subnet

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