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A 150-Ohm resistor is connected in series with a 0.250-h inductor. The voltage a

ID: 2246250 • Letter: A

Question


A 150-Ohm resistor is connected in series with a 0.250-h inductor. The voltage across the resistor is vr = (3.05 V)cos[(525 rad/s)t], Derive an expression for the circuit current. (Assume the frequency is in rad/s. Do not include units in your expression. Use the following as necessary: t.) Determine the inductive reactance of the inductor. Derive an expression for the voltage VL across the inductor. (Assume the frequency is in rad/s and all other values are in MKS. Do not include units in your expression. Use the following as necessary: t.)

Explanation / Answer

v = L di/dt

= 0.25 d(0.02cos(525t) /dt

= 0.25 * 0.02 * 525 [-sin(525t)]

= -.2.625 sin(525t)

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