The thin glass shell shown in the figure has a spherical shape with a radius of

Question

The thin glass shell shown in the figure has a spherical shape with a radius of curvature of 9.5 cm, and both of its surfaces can act as mirrors. A seed 3.3 mm high is placed 15.0 cm from the center of the mirror along the optic axis

PART A

calculate the location of the image this seed

PART B

calculate the height of the image of this seed

PART C

suppose now that the shell is reversed

Find the location of the seed's image

PART D

Fing the height of the seeds image

The thin glass shell shown in the figure has a spherical shape with a radius of curvature of 9.5 cm, and both of its surfaces can act as mirrors. A seed 3.3 mm high is placed 15.0 cm from the center of the mirror along the optic axis calculate the location of the image this seed calculate the height of the image of this seed suppose now that the shell is reversed Find the location of the seed's image Fing the height of the seeds image

Explanation / Answer

A) mirror formula ; 1/v +1/u = 1/f

here f = r/2 =9.5/2 = 4.75 cm.

==) 1/v = 1/4.75 - 1/15 = 0.143

==) v =6.95 cm

B) M = height of (image / object) = - (v/u)

==) height of image = - (6.95 * 3.3 / 15) = -1.53 mm

Note : negative sign implies that the image is inverted.

C) Here the mirror acts as convex mirror , so the focus and object are on opposite sides.

==) 1/v = 1/f - 1/u = 1/(- 4.75) - 1/15 = - 0.277

==) v = - 3.607 cm.

i.e; the object and image are on opposite sides of mirror.

D) M = height of (image / object) = - (v/u)

==) height of image = - ( (-3.607) * 3.3 / 15) = 0.793 mm

Note : Here the imge is erect.

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