A ball and a thin plate are made from different materials and have the same init

Question

A ball and a thin plate are made from different materials and have the same initial temperature. The ball does not fit through a hole in the plate, because the diameter of the ball is slightly larger than the diameter of the hole. However, the ball will pass through the hole when the ball and the plate are both heated to a common higher temperature. In each of the arrangements in the drawing the diameter of the ball is 1.0

A ball and a thin plate are made from different materials and have the same initial temperature. The ball does not fit through a hole in the plate, because the diameter of the ball is slightly larger than the diameter of the hole. However, the ball will pass through the hole when the ball and the plate are both heated to a common higher temperature. In each of the arrangements in the drawing the diameter of the ball is 1.0 times 10-5 m larger than the diameter of the hole in the thin plate, which has a diameter of 0.10 m. The initial temperature of each arrangement is 27.0 degree C. At what temperature will the ball fall through the hole in each arrangement?

Explanation / Answer

You need the coefficients of expansion of the material the plate is made from, and of gold, steel and quartz. If you aren't given these you will have to look them up.

To show you the method, let's make up the coefficient of expansion of the material the plate is made from. Suppose it is 2.00x10^-5 /?C.

Coefficient of expansion of gold 1.42x10^-5 /?C (look it up in data table if not given it in the question)

Diameter of hole at 27.0

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.