Twenty loops of wire are tightly wound around a round pencil that has a diameter

Question

Twenty loops of wire are tightly wound around a round pencil that has a diameter of 5.79 mm. The pencil is then placed in a uniform 4.93-T magnetic field, as shown in the figure. If a 3.15-A current is present in the coil of wire, what is the magnitude of the torque on the pencil?

Twenty loops of wire are tightly wound around a round pencil that has a diameter of 5.79 mm. The pencil is then placed in a uniform 4.93-T magnetic field, as shown in the figure. If a 3.15-A current is present in the coil of wire, what is the magnitude of the torque on the pencil?

Explanation / Answer

Torque = NIABSin(60 degree)

= 20*3.15*pi*(0.5*5.79*10^-3)^2*4.93*Sin(60 degree)

= 0.00708 Nm

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