7.16 A physics TA pushes a 20.0-kg equipment cart at a constant velocity a dista

Question

7.16

A physics TA pushes a 20.0-kg equipment cart at a constant velocity a distance of 28.0 m down the hall. The force she exerts on the cart is directed at an angle 29.0

A physics TA pushes a 20.0-kg equipment cart at a constant velocity a distance of 28.0 m down the hall. The force she exerts on the cart is directed at an angle 29.0 degree below the horizontal and force of friction opposing the motion of cart is 30.0 N. Determine the following. magnitude of the force exerted on the cart by the TA work done by the force the TA exerts on the cart What is the principal concept needed in order to solve this problem? Have you drawn a diagram which shows all the given information? Can you determine an expression for the work done by the force the TA exerts in terms of given quantities? J (c) work done by the force of friction acting on the cart What is the principal concept needed in order to solve this problem? Have you drawn a diagram which shows all the given information? Can you determine an expression for the work done by the force of friction in terms of given quantities? J

Explanation / Answer

b) that will be equal to heat dissipated in friction

=> since constant velocity , friction force = 30 N

work done = 30*28 = 840 joule

c) same as above = 840 joule

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