A mass m falls from a height h (see figure 4) on to an uncompressed spring of sp

Question

A mass m falls from a height h (see figure 4) on to an uncompressed spring of spring constant k. (Express your answer in terms of m, k, h and g.)

(a) How fast is the mass going when it is just about to hit the spring?
(b) How far does it depress the spring? That is, what is the distance Y in terms of m, k, h, g?

A mass m falls from a height h (see figure 4) on to an uncompressed spring of spring constant k. (Express your answer in terms of m, k, h and g.) How fast is the mass going when it is just about to hit the spring? How far does it depress the spring? That is, what is the distance Y in terms of m, k, h, g?

Explanation / Answer

from v^2-u^2=2*g*h.....

here v is the speed of mass before hitting the spring

u is then initial velocity =0

h is height from which mass released,........

v^2=2*g*h....

speed v=sqrt(2*g*h)

B)

energy possed by mass at height h(P.E)=energy possed by compressed spring(Elastic P.E)

mg(h) = (1/2)kY^2

Y^2=2*mgh/k

Y = sqrt[2mgh/k]

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