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Part A A box of mass m and initial speed v 0 slides distance d across a horizont

ID: 2243880 • Letter: P

Question

Part A A box of mass m and initial speed v0 slides distance d across a horizontal floor before coming to rest. Use work and energy to find an expression for the coefficient of kinetic friction.
Express your answer in terms of the variables v0, d, and free fall acceleration g.   ?k = SubmitMy AnswersGive Up Part B A baggage handler throws a 11kg suitcase along the floor of an airplane luggage compartment with a speed of 1.2 m/s. The suitcase slides 2.3m before stopping. What is the suitcase's coefficient of kinetic friction on the floor?   ?k = SubmitMy AnswersGive Up Part A A box of mass m and initial speed v0 slides distance d across a horizontal floor before coming to rest. Use work and energy to find an expression for the coefficient of kinetic friction.
Express your answer in terms of the variables v0, d, and free fall acceleration g.   ?k = SubmitMy AnswersGive Up Part A A box of mass m and initial speed v0 slides distance d across a horizontal floor before coming to rest. Use work and energy to find an expression for the coefficient of kinetic friction.
Express your answer in terms of the variables v0, d, and free fall acceleration g.   ?k = SubmitMy AnswersGive Up   ?k =   ?k = SubmitMy AnswersGive Up Part B A baggage handler throws a 11kg suitcase along the floor of an airplane luggage compartment with a speed of 1.2 m/s. The suitcase slides 2.3m before stopping. What is the suitcase's coefficient of kinetic friction on the floor?   ?k = SubmitMy AnswersGive Up Part B A baggage handler throws a 11kg suitcase along the floor of an airplane luggage compartment with a speed of 1.2 m/s. The suitcase slides 2.3m before stopping. What is the suitcase's coefficient of kinetic friction on the floor?   ?k = SubmitMy AnswersGive Up   ?k =   ?k = SubmitMy AnswersGive Up   ?k =

Explanation / Answer

Here


0.5*m*v0^2 = umg*d


Therefore


0.5*v0^2 = ugd


u = 0.5v0^2/(gd)



u = (0.5*1.2*1.2)/(9.8*2.3)


= 0.0139

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