A 1 195.0 kg car traveling initially with a speed of 25.000 m/s in an easterly d
ID: 2243879 • Letter: A
Question
A 1 195.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 100.0 kg truck moving in the same direction at 20.000 m/s. The velocity of the car right after the collision is 18.000 m/s to the east.
A 1 195.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 100.0 kg truck moving in the same direction at 20.000 m/s. The velocity of the car right after the collision is 18.000 m/s to the east. What is the velocity of the truck right after the collision? (Give your answer to five significant figures.) What is the change in mechanical energy of the car-truck system in the collision?Explanation / Answer
i) the coneservation of mometum would takes place
so m1u1+m2u2=m1v1+m2v2
where u and v are signs for intial velocity and final velocity resp.
so 1195.0*25+9100*20=211875.000kgm.s=1195*18.00+9100*v2
v2=20.91923077m/s
ii) change in mechanical energy of the car-truck system
=intial kinetic energy=2193437.5000J
final kinetic energy=2184728.8250J
so lose in kinetic energy=8768.6750J
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