1) A very thin horizontal, 2.00-m long, 5.00-kg uniform beam that lies along the

Question

1) A very thin horizontal, 2.00-m long, 5.00-kg uniform beam that lies along the east-west direction is acted on by two forces. At the east end of the beam, a 200-N force pushes downward. At the west end of the beam, a 200-N force pushes upward. What is the angular acceleration of the beam?

2) A stationary 1.67-kg ball is struck by a stick. The ball experiences a horizontal force given by

F = (77 N/s) t - (27 N/s2) t2, where t is the time in seconds from the instant the stick first contacts the ball. Calculate is the speed of the ball just after it comes away from the stick at t = 2.74 s.

3) The tensile strength (the maximum tensile stress it can support without breaking) for a certain steel wire is 3000

MN/m2. What is the maximum load that can be applied to a wire with a diameter of 3.0 mm made of this steel without breaking the wire?(The Young modulus for steel is 20

Explanation / Answer

1)angular acceleration = 200*2.00)/[5.00*2.00^2)/12] = (400*12)/20 = 240 rad/s^2

2)

3)3000 MN/m^2 x pi x (0.003m / 4)^2 = 21.2 kN

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