A 33.2 kg beam is attached to a wall with a hinge and its far end is supported b

Question

A 33.2 kg beam is attached to a wall with a hinge and its far end is supported by a cable. The angle between the beam and the cable is 90o. If the beam is inclined at an angle of ? = 29.5

33.2 kg beam is attached to a wall with a hinge and its far end is supported by a cable. The angle between the beam and the cable is 90o. If the beam is inclined at an angle of ? = 29.5 degree with respect to horizontal. What is the horizontal component of the force exerted by the hinge on the beam? (Use the 'to the right' as + for the horizontal direction.) What is the magnitude of the force that the beam exerts on the hinge? Please explain in as much detail as possible and write out formulas used.

Explanation / Answer

T*cos(90-29.5) = Fx

T*sin(90-29.5) + Fy = Mg


T*sin(90-29.5)*L*sin29.5 = Mg*cos29.5*(L/2)

T = 330.36 N

Fx= 162.68 N

Fy = 37.82

F = 167.01 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.