In the figure, water flows through a horizontal pipe and then out into the atmos
ID: 2242584 • Letter: I
Question
In the figure, water flows through a horizontal pipe and then out into the atmosphere at a speed v1 = 16.0 m/s. The diameters of the left and right sections of the pipe are 5.20 cm and 3.00 cm. What is the pressure in section 2? in Pa
Hint:What is the volume flow rate at the open end? How do you determine the total volume in the given time interval? Did you relate the two speeds via the equation of continuity? Did you realize that the pressure at the open end must be atmospheric pressure? Did you then relate the two pressures via Bernoulli's equation?
In the figure, water flows through a horizontal pipe and then out into the atmosphere at a speed v1 = 16.0 m/s. The diameters of the left and right sections of the pipe are 5.20 cm and 3.00 cm. What is the pressure in section 2? in Pa Hint:What is the volume flow rate at the open end? How do you determine the total volume in the given time interval? Did you relate the two speeds via the equation of continuity? Did you realize that the pressure at the open end must be atmospheric pressure? Did you then relate the two pressures via Bernoulli's equation?Explanation / Answer
A1*v1 = A2*V2
(pi*d1^2/4)*v1 = (pi*d2^2/4)*v2
v2 = v1*(d1/d2)^2
= 16*(5.2/3)^2
= 48.07 m/s
according to bernoulli's principle
P1+0.5*rho*v1^2 = P2 + 0.5*rho*v2^2
P1 - P2 = 0.5*rho*(v2^2-v1^2)
= 0.5*1000*(48.07^2 - 16^2)
= 1027415.86 pa
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