A 2.40 kg box slides down a rough incline plane from a height h of 1.75 m. The b

Question

A 2.40 kg box slides down a rough incline plane from a height h of 1.75 m. The box had a speed of 2.55 m/s at the top and a speed of 2.12 m/s at the bottom. Calculate the mechanical energy lost due to friction (as heat, etc.).

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A 2.40 kg box slides down a rough incline plane from a height h of 1.75 m. The box had a speed of 2.55 m/s at the top and a speed of 2.12 m/s at the bottom. Calculate the mechanical energy lost due to friction (as heat, etc.).

Explanation / Answer

Energy Lost due to Friction is total energy on top - total energy on bottom 1/2(m((vtop)^2) + mgh -1/2(m(vbottom)^2)) = 7.8 + 41.2 - 5.4 = 43.6 .

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