1. If the temperature change in this experiment is 29 degrees celcius, then what

Question

1. If the temperature change in this experiment is 29 degrees celcius, then what would be the temperature change in Fahrenheight? Also in Kelvin?   (NOTE THIS DOENST SAY CONVERT 29 to the other temperatures because   I can do that)

2. The initial equation that will be used to find the specific heat of the sample in this experiment is QL + QG =0 (heat lost plus heat gained =0 for a closed system. Write the specific form of this equation needed in this experiment in order to calculate the specific heat of the sample.

3. How would the calculated value of the specific heat of the sample be affected if some heated water is accidently transferred, with the sample, to the calorimeter. Explain.

4. The specific heat of water is 1.00 cal/g Celcius or 4.19 J/gCelcius.  If the specific heat of copper is .39 J/gCelcius, what is its specific heat in

     a. cal/gCelcius

    b. Kcal/KgCelcius

Explanation / Answer

1) dF = (9/5)*dC = (9/5)*29 = 52.2 f

dK = dC = 29 K

2)

3) no change

4)a) 0.39/4.186 = 93.168e?3 cal/g celsius

b) 93.168e?3 Kcal/Kg celsius

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