please show work please The symbol 1/4 pi epsilon 0 appears in Coulomb\'s law be
ID: 2241945 • Letter: P
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please show work please
The symbol 1/4 pi epsilon 0 appears in Coulomb's law because we use independently defined units for force and distance. force, distance and electric charge distance and force charge Answer: B Imagine for a minute that the moon is held in its orbit about the Earth by electrical forces rather than by gravitation. What electrical charges -Q on the Earth and +Q on the moon are necessary to hold the moon in a circular orbit with a period of 27.3 days? The Earth -moon distance is 384,000 km and the mass of the moon is 7.35 times 1022 kg. (Hint: Velocity = Distance. Time) Answer: Q = 5.73 times 1013CExplanation / Answer
The force of attraction will be K*Q^2 / d^2
The centrifugal force is m*v^2 / d
Equate these to get
K*Q^2 / d^2 = m*v^2 / d
Q = ?[m*v^2*d/K]
d is distance from center of the earth, 3.84*10^8 m
m = 7.35*10^22, m K = 9*10^9 N*m^2/C^2
v must be in m/s One orbit is 2*?*390.4*10^6m and takes 27.3 days or 2.359*10^6 sec. The velocity is then 1040 m/s
Q = ?[7.35*10^22*1.082*10^6*384*10^6/(9*10^9...
Q = 5.83*10^13 C (if I did my arithmetic right)
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