A system comprising two blocks is shown, one of which is on an inclined plane. T
ID: 2241243 • Letter: A
Question
Explanation / Answer
delta KA = +330 J
delta UA = -588 J
delta KB = 110 J
delta UB = +98 J
work done by friction = delta KA +delta UA + delta KB + delta UB
wf = 330-588+110+98
= -50 J
woek done by friction is disipated as heat
Q = 50 J
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