As part a of the drawing shows, two blocks are connected by a rope that passes o
ID: 2240891 • Letter: A
Question
As part a of the drawing shows, two blocks are connected by a rope that passes over a set of pulleys. One block has a weight of m1 = 412 N, and the other has a weight of m2 = 858 N. The rope and the pulleys are massless and there is no friction.
(a) What is the acceleration of the lighter block?
m/s2
(b) Suppose that the heavier block is removed, and a downward force of 858 N is provided by someone pulling on the rope, as part b of the drawing shows. Find the acceleration of the remaining block.
m/s2
(c) Explain why the answers in (a) and (b) are different.
Explanation / Answer
a)suppose T is the tension in the rope and a is the acceleration of the masses.
Mg-T=Ma .......1
T-mg=ma .............2
adding Mg-mg=(m+M)a
446=129.59a (g=9.8m/s^2)
a=3.44m/s^2
b)
In this case T is 858 N
so T-mg=ma
=>(858-412)/42.04=a
a=10.6
c)
Tension in both cases are different .
In the first case we find the tension using 1 and 2
in second case tension is 858N
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