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%3Cp%3EWhen%20it%26nbsp%3Borbited%26nbsp%3Bthe%26nbsp%3BMoon%2C%26nbsp%3Bthe%26nbsp%3BApollo%26nbsp%3B11%26nbsp%3Bspacecraft%E2%80%99s%26nbsp%3Bmass%26nbsp%3Bwas%26nbsp%3B13900%26nbsp%3Bkg%2C%26nbsp%3Band%26nbsp%3Bits%26nbsp%3Bmean%26nbsp%3Bdistance%26nbsp%3Bfrom%26nbsp%3Bthe%26nbsp%3BMoon%E2%80%99s%26nbsp%3Bcenter%26nbsp%3Bwas%3C%2Fp%3E%3Cp%3E2.03322%26nbsp%3B%C3%97%26nbsp%3B106%26nbsp%3Bm.%26nbsp%3B%3C%2Fp%3E%3Cp%3EA.%26nbsp%3BFind%26nbsp%3Bthe%26nbsp%3Borbital%26nbsp%3Bspeed%26nbsp%3Bof%26nbsp%3Bthe%26nbsp%3Bspacecraft.%26nbsp%3BAssume%26nbsp%3Bits%26nbsp%3Borbit%26nbsp%3Bto%26nbsp%3Bbe%26nbsp%3Bcircular%26nbsp%3Band%26nbsp%3Bthe%26nbsp%3BMoon%26nbsp%3Bto%26nbsp%3Bbe%26nbsp%3Ba%26nbsp%3Buniform%26nbsp%3Bsphere%26nbsp%3Bof%26nbsp%3Bmass7.36%26nbsp%3B%C3%97%26nbsp%3B1022%26nbsp%3Bkg.%26nbsp%3BThe%26nbsp%3Bgravitational%26nbsp%3Bconstant%26nbsp%3Bis%26nbsp%3B6.67259%26nbsp%3B%C3%97%26nbsp%3B10%3F11%26nbsp%3BN%26nbsp%3B%C2%B7%26nbsp%3Bm2%2Fkg2%26nbsp%3BAnswer%26nbsp%3Bin%26nbsp%3Bunits%26nbsp%3Bof%26nbsp%3Bm%2Fs%3C%2Fp%3E%3Cp%3E%3Cbr%3E%3C%2Fp%3E%3Cdiv%3E%3Cdiv%3EB.What%26nbsp%3Bis%26nbsp%3Bthe%26nbsp%3Bminimum%26nbsp%3Benergy%26nbsp%3Brequired%26nbsp%3Bfor%26nbsp%3Bthe%26nbsp%3Bcraft%26nbsp%3Bto%26nbsp%3Bleave%26nbsp%3Bthe%26nbsp%3Borbit%26nbsp%3Band%26nbsp%3Bescape%26nbsp%3Bthe%26nbsp%3BMoon%E2%80%99s%26nbsp%3Bgravitational%26nbsp%3B%3Feld%3F%3C%2Fdiv%3E%3Cdiv%3EAnswer%26nbsp%3Bin%26nbsp%3Bunits%26nbsp%3Bof%26nbsp%3BJ%3C%2Fdiv%3E%3C%2Fdiv%3E

Explanation / Answer

A ) V = sqrt(GM/r = sqrt((6.67259*10^-11*7.36*10^22)/(2.03322*10^6)) = 1554.15 m/s = 1.55415km/s

B) U = -GMm/2r = -(6.67259*10^-11*7.36*10^22*13900)/(2*2.03322*10^6) = 16.787e+9 J

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