Question: Suppose a communications satellite orbits Earth above the equator (r=6

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Question: Suppose a communications satellite orbits Earth above the equator (r=6.41E6 [m]) at a speed of 7500 [m/s] Eastward. The B-field is about 50[microTesla] Northward, there, so electrons in the metal will be pushed by it {which direction?} Electrons will continue to accumulate at the metal surface (leaving + ion cores behind) until the charge separation makes enough Force (from its E-field) to cancel the Force from the magnetic field. What is that electric field? Answers: Zero 60E-21 [V/m] upward 60E-21 [V/m] downward 0.375 [V/m] upward 0.375 [V/m] downward 214,000 [V/m] upward 214,000 [V/m] downward

Explanation / Answer

we know that force on charge q due to magnetic field B is given by F= qVcross parodut with B...... now since q is negative as in case of electron so we have direction of force on electron will be downward by taking dot produt and multyplying it with -ve sign................................................................also force due to EF on charge q= qE.....so let we have qE=QVB........or E=VB,..............or E= 7500 * 50*19^-6.............=downward 0.375 [V/m] ........................because electrons will accumulate downward so ef will be from positive to negative...

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