1. An ac generator has a frequency of 2.5 kHz and a voltage of 240 V. An inducta
ID: 2239445 • Letter: 1
Question
1. An ac generator has a frequency of 2.5 kHz and a voltage of 240 V. An inductance L1 =4.0 mH is connected across its terminals. Then a second inductance L2 =8.0 mH is connected in parallel with L1. Find (a) the current that the generator delivers to L1 and (b) to the parallel combination. 2. There is no resistance in the circuit. The electrical energy initially present in the charged capacitor then oscillates back and forth between the inductor and the capacitor. The initial charge on the capacitor has a magnitude of q = 3.20 ?C. The capacitance is C = 3.50 ?F, and the inductance is L = 85.0 mH. (a) What is the electrical energy stored initially by the charged capacitor? Energy = (b) Find the maximum current in the inductor. Imax = *Note: If you could please show all of your work that would be great. I learn best by seeing how it was solved. Thank you everyone for your help and input!Explanation / Answer
1.
inductive reactance
XL1 =2pifL1 =2pi*2500*4*10^-3 =62.83 ohms
I1=V/XL1 =240/62.83
I1=3.82 A
b)
equivalent inductance
L=L1*L2/(L1+L2) =4*8/(4+8)=2.67mH
XL =2pifL =2pi*2500*2.67*10^-3 =41.9 ohms
IL =V/XL =240/41.9
IL=5.73A
2.
a)
E=Q^2/2C =(3.2*10^-6)^2/2*3.5*10^-6
E=1.46*10^-6 J or 1.46uJ
b)
Estored in capacitor =Energy stored in inductor
1.46*10^-6 =(1/2)LI^2 =(1/2)*85*10^-3*i^2
i=5.87*10^-3 a OR 5.87mA
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