A bat hits a moving baseball. If the bat delivers a net eastward impulse of 1.5

Question

A bat hits a moving baseball. If the bat delivers a net eastward impulse of 1.5 N-s and the ball starts with an initial horizontal velocity of 3.8 m/s to the west and leaves with a 4.9 m/s velocity to the east, what is the mass of the ball (in grams)?

Explanation / Answer

impulse = Force * time = m[v - u] = change in momentum lets use vectors > unit vector (+i) along east and (- i) along west ----------------------- 1.5 (+i) = final momentum - initial momentum 1.5 (+i) = m* (4.9*(+ i) - m (3.8) (- i) 1.5 (+i) = m* (4.9)*(+ i) + m (3.8) (+i) 1.5 = m* (4.9) + m (3.8) = 8.7 m m = mass = 1.5/8.7 kg m = 172.41gram

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