A3.20-N metal bar, 1.55m long and having a resistance of 10.0 ohm , rests horizo

Question

A3.20-N metal bar, 1.55m long and having a resistance of 10.0 ohm , rests horizontally on conducting wires connecting it to the circuit shown in the figure (Figure 1). The bar is in a uniform, horizontal, 1.85-T magnetic field and is not attached to the wires in the circuit. What is the magnitude of the acceleration of the bar just after the switch s is closed? a = m/s What is the direction of the acceleration of the bar just after the switch S is closed? Upward To the right Downward To the left

Explanation / Answer

R' = (1/10 + 1/10)^-1

= 5 ohms

R = 25 + 5 = 30

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I = V / R

= 120 / 30

= 4 A

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Vb = I*R'

= 4*5

= 20 V

Ib = Vb / Rb

= 20 / 10

= 2 A

====================

a = (Ib*L*B/mg - 1)g

= (2*1.55*1.85/3.2 - 1)*9.8

= 7.763 m/s^2

=====================

b)

the direction of the acceleration of the bar just before the switch is closed is upwards

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