A block of mass M is on the incline plane that has angle theta with horizontal a

Question

A block of mass M is on the incline plane that has angle theta with horizontal axis x. The y-axis is directed vertically up. The weight of the block is known The coefficient of kinetic friction between the block and the incline plane is mu. Initially the block is at rest, then the block is sliding down distance L. What is the acceleration of the block? What is the initial kinetic energy? What is the velocity of the block after it has passed distance L? What is the kinetic energy of the block after it has passed distance L? What is the work done by the weight force ? What is the work done by the normal force? What is the work done by the friction force? From previous answers, compare the change of the kinetic energy of the block and the sum of work done by all forces. Show that the work-energy theorem is working.

Explanation / Answer

1) acceelration = g (sin theta ,- u. cso theta)

2) initail K.E = 1/2.m x 0 = 0

3) V^2 = 2 x g (sin theta ,- u. cso theta) x L

so, V = sqrt (2.g.(sin t - u.cos t).L)

4) K.E. = 1/2 x m x 2 x g (sin theta ,- u. cso theta) x L

5) work done by W = W.sin theta x L

6) normal foce work = 0

7) work by fricton force= - u.m.g.cso theta x L

8) change in K.>E = 1/2.m. g (sin theta ,- u. cso theta) x L

work by all forces = W.sin theta x L - u.m.g.cso theta x L

= m.g. (sin theta ,- u. cso theta) x L

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.