you watch kids playing soccer on field a bout 200 m away from you. you notice th

Question

you watch kids playing soccer on field a bout 200 m away from you. you notice that there is a time-delay between the time you see a kid kick the ball and the time you hear the thud of that that kick. you have a stop watch capable of measuring milliseconds, so you time the delay several times. you come up with the following values for different trials:
580 ms, 583 ms, 590 ms, 575 ms and 593 ms.(ms stand for milliseconds). find the average vaule for those times, and calculate the speed of sound in air. copare that with with the accepted value of 768 mph , that is , find the % difference between your average measured value and the accepted value. remember that 5 miles = 8 km?

Explanation / Answer

1) AVERAGE=(580+583+575+593)/4=582.75 MSEC 2) SPEED v=D/t=200/582.75e-3=343.2 m/sec 3) 768 mph= 1228.8 km/h = 341.3 m/sec 4) % diff ( 341.3-343.2)*100/343.2=0.55 %

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