The circuit shown in the figure below is connected for 3.50 min. (Assume R1 = 6.

Question

The circuit shown in the figure below is connected for 3.50 min. (Assume R1 = 6.80 Ohm, R2 = 1.70 Ohm, and V = 15.0 V.) Image: http://www.webassign.net/serpse8/28-p-021-alt.gif (a) Determine the current in each branch of the circuit. left branch _____(A) middle branch _____(A) right branch _____(A) (b) Find the energy delivered by each battery. 4.00 V battery ____ J 15.0 V battery ____kJ (c) Find the energy delivered to each resistor. 6.00 O resistor _____ J 5.00 O resistor _____ J 1.00 O resistor _____ J 3.00 O resistor _____ J 1.70 O resistor _____ J (d) Identify the type of energy storage transformation that occurs in the operation of the circuit. (e) Find the total amount of energy transformed into internal energy in the resistors. (kJ)

Explanation / Answer

Applying Kirchoff's laws..(voltage law and current law)

I (left branch) = 1.4084 A upwards.

I (middle branch) = 0.93 A downwards

I(right branch) = 1.1496 A upwards.

Energy from 4 V battery = VIt = 4*0.93*(3.50*60) = 781 J

Energy from 15 V battery = 15*1.1496*210 = 3.62 KJ

Energy in any resistor = (I(across R)*I(across R)/R) *t

Chemical energy of battery converts to Electrical Energy of circuit and then internal

energy of the resistors.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.