Suppose a 31.5 kg child sits 1.55 m to the left of center on the same seesaw as

Question

Suppose a 31.5 kg child sits 1.55 m to the left of center on the same seesaw as the problem you just solved. A second child sits at the end on the opposite side, and the system is balanced.

(a) Find the mass of the second child.

(b) Find the normal force acting at the pivot point.

Suppose a 31.5 kg child sits 1.55 m to the left of center on the same seesaw as the problem you just solved. A second child sits at the end on the opposite side, and the system is balanced. (a) Find the mass of the second child. (b) Find the normal force acting at the pivot point.

Explanation / Answer

the torques shall be the same --> 31.5*2=m*1.55 --> m=40.64 kf N=F=m1g+m2g=g(m1+m2)=9.8*(31.5+40.64)=707.02 N

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