Two negative charges, Q = -35 are placed on the x-axis at x = +0.45 m and x = -0

Question

Two negative charges, Q = -35 are placed on the x-axis at x = +0.45 m and x = -0.45 m. a)How much energy does it take to assemble these two charges? b)You place an unknown charge on the y-axis at y = 0.9 m and find that the electric potential is 0 V at the origin. What is the unknown charge? c)If you place a -5 charge at the origin, what is the x-component of the force on it from the other three charges? d)If you place a -5 charge at the origin, what is the y-component of the force on it from the other three charges?

Explanation / Answer

you didnt give any units so you might need to recalculate with correct units

a) PE = k q1 q2/r = 9E9*(35)^2/(.9)=12.25E12

b) V = 2*k*-35/0.45 +k Q/0.9 = 0

2*-35 + Q/2 = 0

Q = 4*35 = 140

c) both - charges will pull at it the same amount so Fx = 0

d) Fy = k q1 q2/r ^2 = 9E9*140*5/0.9^2=7.78E12 N

Remember you will have to recaculate with correct units

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