Lead has a latent heat of fusion of 2.32 x 10^4 J/kg and a specific heat of 128

Question

Lead has a latent heat of fusion of 2.32 x 10^4 J/kg and a specific heat of 128 J/ (kg K), and a melting point of 228 degrees Celsius. The ambient temperature is 16 degrees Celsius. A 30 g lead bullet hits a solid surface and comes to a complete stop. What would the velocity of the bullet have to be in order for it to melt completely when it hits the wall, assuming that all its kinetic energy is transformed into heat? A) calculate heat needed to raise temperature to melting point? B) calculate heat needed to melt the bullet? C) determine velocity needed to achieve melting the bullet?

Explanation / Answer

a)Heatneeded to raise temperature to melting point=mCp(Tf-Ti)=814J

b)heat needed to melt the bullet=mL=696J

c)Total Kinetic energy=total heat generated

0.5mv^2=1510

v=317.3m/s

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