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I am having an issue with this problem.. but before you look at it, please take

ID: 2233078 • Letter: I

Question

I am having an issue with this problem.. but before you look at it, please take this into consideration....


This problem has been solved... this problem also has an answer from a solution manual. This is all great, but masteringphysics.com where hw is to be turned in doesnt accept the solution... I will take a screen shot of the answer and what the solution should be.... then I will post what it accepted as one of the answer, and what it wont accept as what I believe to be the correct answer.


The only reason I have part c correct is because we get unlimited guesses, and I got so fed up that I started to put every number in until it said it was correct. If someone can look at the problem, and see that the solution manual is different, then look back at the problem again, and maybe make sense of how they got the answer..


This is problem 24.28 from "physics for scientists and engineers" by knight 2nd edition

For part D, 1.3 doesn't work either.... also, I tried my method that worked for part c... but that didnt work..


I would suspect that the image in the mirror should be smaller than the original or close to it... but as you can see from part a and b... it doesnt make sense to me that the image would be real at all... it doesnt make sense that it is the the left of the lens..


the only 30 I could think of was when you has s and s'=-10


and s1=15 on and s'1=-10 and s=5cm


10+10+15-5=30 ???


Please help with any ideas.


Explanation / Answer

1/10 =1/5 +1/v v = -10 ie 10 cm to the left of first hence for lense with f =-30 object distance u =15 ie(10+5) hence 1/30 =1/15 +1/v hence v = -30 ie final image is 30 cm from the lens of focal length 30cm