Part A Calculate the heat released as 11.0 of liquid water at 100 is cooled to 5

Question

Part A Calculate the heat released as 11.0 of liquid water at 100 is cooled to 50.0 . Part B Calculate the heat released when 11.0 of steam at 100 is condensed and cooled to 50.0 . Part C Find the mass of flesh that can be heated from 37.0 (normal body temperature) to 50.0 for the case considered in part A. (The average specific heat of flesh is 3500 .) Part D Find the mass of flesh that can be heated from 37.0 (normal body temperature) to 50.0 for the case considered in part B. (The average specific heat of flesh is 3500 .)

Explanation / Answer

a) Q = m*c*?T = 0.0148kg*4.186kJ/kg-oC*(100-50) = 3.10kJ b) Now we have the same Q as a but with the addition of heat to condense the steam Q = m*Lv = 0.0148kg*2.256x10^3kJ/kg = 33.4kJ so the total Q = 33.4 + 3.10 = 36.5kJ c) a) Q = m*c*?T => m = Q/(c*?T) = 3100J/(3800*13) = 0.0628kg b) Q = m*c*?T => m = Q/(c*?T) = 36500J/(3800*13) = 0.739kg

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