A small glass bead has been charged to +25 nC. What is the magnitude of the acce

Question

A small glass bead has been charged to +25 nC. What is the magnitude of the acceleration of a proton that is 1.0 cm from the center of the bead? What is the direction of the acceleration of a proton that is 1.0 cm from the center of the bead? (toward the bead or away from the bead)

What is the magnitude of the acceleration of an electron that is 1.0 cm from the center of the bead?
What is the direction of the acceleration of an electron that is 1.0 cm from the center of the bead? (toward the bead or away from the bead)

Explanation / Answer

9 * 10^9 * 25* 10^-9 *1.6 * 10^-19 * 10000 / 9.107 * 10^-34 = a a = 39.53 * 10^ [ 19 ] m/sec^2

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