A hanging mass, M1 = 0.18 kg, is attached by a light string that runs over a fri

Question

A hanging mass, M1 = 0.18 kg, is attached by a light string that runs over a frictionless pulley to the front of a mass M2 = 0.36 kg that is initially at rest on a frictionless table. A third mass M3 = 0.66 kg, which is also initially at rest on a frictionless table, is attached to the back of M2 by a light string. (a) Find the magnitude of the acceleration, a, of mass M3. (b) Find the tension in the string between masses M1 and M2.

Explanation / Answer

a) acceleration is same for all the 3 pulley so by newton third law 0.18*g-T=0.18a T=(0.36+0.66)*a ----->1 solving these two we get a=1.47 m/s^2 b)T=(0.36+0.66)*1.47 by eqn 1) T=1.5 N ans

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