In the figure, 2.45 mole of an ideal diatomic gas can go from a to c along eithe

Question

In the figure, 2.45 mole of an ideal diatomic gas can go from a to c along either the direct (diagonal) path ac or the indirect path abc. The scale of the vertical axis is set by p ab = 6.47 kPa and p c = 2.35 kPa, and the scale of the horizontal axis is set by V bc = 6.15 m3 and V a = 2.96 m3. (The molecules rotate but do not oscillate.) What is the net transfer of energy as heat for the indirect path?

Explanation / Answer

By Mohsen ------------------------------------------------------------------------------------ Q = 5/2 n R ?T ==> ?Ta = T2 - T1 = (P1V2-P1V1)/nR ==> ?Ta = (6470*6.15-6470*2.96)/(2.45*8.314) ==> ?Ta = 1013.3 T ==> Qa = 5/2 n R ?T ==> Qa = (5/2) * 2.45 * 8.314 * (1013.3) ==> Qa = 51601 J ==> ?Tb = T2 - T1 = (P1V2-P1V1)/nR ==> ?Tb = (2350*6.15-6470*6.16)/(2.45*8.314) ==> ?Tb = -1247.11 T ==> Qb = 5/2 n R ?T ==> Qb = (5/2) * 2.45 * 8.314 * (-1247.11) ==> Qb = -63506.9 J ==> Q = 51601 - 63507 = -11906 J

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