(II) extreme -sports enthusiasts have been known to jump off the top of El Capit

Question

(II) extreme -sports enthusiasts have been known to jump off the top of El Capitan, a sheer granite cliff of height 910 m in yosemite nation park. Assume a jumper runs horizontally off top El Capitan with speed 5.0 m/s and enjoys a freefall until she is 15o m above the valley floor, at which time she opens her parachute (fig. 3-41). (a) how long is the jumper in freefall?Ignor dair resistance. (b) it is import to be as far away from the cliff as posible before opening the parachute. how far from the cliff is the jumper when she opens her chute?

Explanation / Answer

for part a, we note that there was no initial vertical velocity, so we can calculate how long she was in free fall from distance = 1/2 gt^2 where g is the accel due to gravity and t is the time here, the distance of freefall = 910 m - 150 m = 760m and find the time from t=sqrt[2*760m/9.8m/s/s] since there are no horizontal forces, the horizontal speed is constant throughout the trip (until the parachute is deployed) therefore, the diver travels a horizontal distance of 5m/s x time of freefall (which you just computed above)

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