Two 20cm -long thin glass rods uniformly charged to +20nC are placed side by sid

Question

Two 20cm -long thin glass rods uniformly charged to +20nC are placed side by side, 4.0 cm apart. What are the electric field strengths E_1, E_2, and E_3 at distances 1.0cm, 2.0cm, and 3.0cm to the right of the rod on the left, along the line connecting the midpoints of the two rods? I received this answer already: "I believe point one could be calculated by E1-(E3/3 Since the linear, uniform charge is inversely, linearly porportional. For E1 I get 1.8E5 N/C; so, 1.8E5 N/C -(1.8E5N/C / 3) = 1.2E5 N/C the answer as 1.25E5 N/C " This is correct, but how did they get 1.8e5 for E1? And how do I find E2 and E3?

Explanation / Answer

E2 = 0, as field will cancel at mid point.

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