Problem 1 A bullet is accelerated in a 6 inch barrel and leaves the muzzle at 77

Question

Problem 1 A bullet is accelerated in a 6 inch barrel and leaves the muzzle at 770 ft/s. (A) Determine the acceleration of the bullet in the barrel assuming that it is constant. (B) Determine the time of travel of the bullet in the barrel. Problem 2 A bullet is accelerated in a barrel and leaves the muzzle at 2800 ft/s. It took 0.001 seconds for the bullet to travel in the barrel, and the acceleration was constant. What is the length of the barrel? Problem 3 A rocket is launched from the ground in vertical direction. But its engine failed at the moment the rocket has reached an altitude of h = 300 ft and a speed of vo = 550 ft/s. Determine the maximum height (from the ground level) that the rocket can reach. Problem 4 A rock is thrown upward from a 40-ft tower with an initial speed of 10 ft/s. Determine the time of travel of the rock (from the moment it was thrown upward until it touches the ground). Problem 5 The track for a racing event was designed so that riders jump off the slope at 30o, from a height of 5 ft. The speed at the tip of the ramp is 60 mph. (A) How long will the rider remain in mid-air before landing? (B) Determine the horizontal distance between the launching ramp and the point of landing.(C) Determine the maximum height he attains.

Explanation / Answer

1) A)v^2-u^2=2as u=0 v=770ft/s s=0.5ft a=V^2/2s a=592,900ft/s^2 t=v/a t=0.001s 2)t=0.001s v=2800ft/s v=u+at a=v/t=2,800,000ft/s^2 s=v^2/2a s=2800*2800/2*2800000 s=1.4ft=16.8inch 3)v0=550ft/s Hmax=u^2/2g H=4726.5ft Total height=H+300=5026.5ft 4)h=u^2/2g h=1.56ft total height=41.56ft time taken to reach 1.56ft=t1=u/g=0.3125s time taken to reach ground from 41.56ft=sqrt(2h/g) t2=1.611s total time=t1+t2=1.92sec

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