If you have five capacitors with capacitances 1.4 times 10-6 F, 2.2 times 10-6 F

Question

If you have five capacitors with capacitances 1.4 times 10-6 F, 2.2 times 10-6 F, 5.4 times 10-6 F, and two 6.7 times 10-6 F in series. What is the equivalent capacitance of all five? C = F Initially the capacitors are uncharged. Now a 14.0 V battery is attached to the system. How much charge is on the positive plate of the 5.4 times 10-6 F capacitor? Q = C What is the potential difference between the plates of the 5.4 times 10-6 F capacitor? V = V How much energy is stored in the entire capacitor system? PE = J If you have five capacitors with capacitances 1.4 times 10-6 F, 2.2 times 10-6 F, 5.4 times 10-6 F, and two 6.7 times 10-6 F in parallel. What is the equivalent capacitance of all five? What is the equivalent capacitance of all five? C = F If one attaches a 14.0 V battery is attached to the system. How much charge is on the positive plate of the 5.4 times 10-6 F capacitor? Q = C What is the potential difference between the plates of the 6.7 times 10-6 F capacitor? V = V How much energy is stored in the entire capacitor system? PE = J

Explanation / Answer

1)1.34x10^-6F 2)Q=CV Q=7.56x10^-5C 4)U=1/2CV^2 U=0.5*1.34x10^-6*14*14 U=1.31x10^-4J

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