Two test charges are located in the x Solution t goes {almost :>} without saying

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t goes {almost :>} without saying that a diagram be made showing the two charges. The E vectors at the origin from each of these charges is then drawn. A vertically upward arrow (vector) along Y-axis represents the E1 vector caused by the -5 nC charge. A vector with its tail at the origin in line with the +4.8 nC charge with its head in the 3rd quadrant represents the E2 vector caused by the +4.8 nc charge. |E| = KQ/d² |E1| = 8.89e9(5e-9)/(1.16)² = 33 N/C {size of E1 vector} |E2| = 8.89e9(4.8e-9)(v1²+0.4²) = 42.67/1.16 = 36.8 N/C {size of E2 vector} E1 vector is already a component in the +Y direction E2 vector has Y-component = E2 (0.4/1.16) = 36.8(0.3448) = -12.7 N/C E2 vector has X-component = E2(1/1.16) = 36.8(0.86207) = -31.7 N/C SX = -31.7 N/C ANS SY = 36.8 - 12.7 = +24.1 N/C ANS

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